Which of the following is equivalent to a≡b(modn)a \equiv b \pmod{n}a≡b(modn)?
n∣an \mid an∣a and n∣bn \mid bn∣b
a=ba = ba=b
n∣(a−b)n \mid (a-b)n∣(a−b)
n∣(a+b)n \mid (a+b)n∣(a+b)