Which of the following is equivalent to ∫1z2−4z+3dz\int \frac{1}{z^2-4z+3} dz∫z2−4z+31dz?
12ln∣z−3z−1∣+C\frac{1}{2}\ln|\frac{z-3}{z-1}| + C21ln∣z−1z−3∣+C
ln∣z−3z−1∣+C\ln|\frac{z-3}{z-1}| + Cln∣z−1z−3∣+C
12ln∣z−1z−3∣+C\frac{1}{2}\ln|\frac{z-1}{z-3}| + C21ln∣z−3z−1∣+C
ln∣z−1z−3∣+C\ln|\frac{z-1}{z-3}| + Cln∣z−3z−1∣+C