Which of these is equivalent to x≡5(mod6)x \equiv 5 \pmod{6}x≡5(mod6)?
x≡1(mod2)x \equiv 1 \pmod{2}x≡1(mod2)
x≡2(mod3)x \equiv 2 \pmod{3}x≡2(mod3)
x≡−1(mod6)x \equiv -1 \pmod{6}x≡−1(mod6)
x≡0(mod6)x \equiv 0 \pmod{6}x≡0(mod6)