Which of these is the solution set for ∣x2−2x∣<3|x^2 - 2x| < 3∣x2−2x∣<3?
(−1,3)(-1, 3)(−1,3)
(1−3,1+3)(1 - \sqrt{3}, 1 + \sqrt{3})(1−3,1+3)
(−1,1)∪(1,3)(-1, 1) \cup (1, 3)(−1,1)∪(1,3)