Which pair (x,y)(x, y)(x,y) satisfies x2−2y2=−1x^2 - 2y^2 = -1x2−2y2=−1?
(1,1)(1, 1)(1,1)
(3,2)(3, 2)(3,2)
(7,5)(7, 5)(7,5)
(1,0)(1, 0)(1,0)