Which statement best describes the Wilson's Theorem property?
(p−1)!≡0(modp)(p-1)! \equiv 0 \pmod{p}(p−1)!≡0(modp)
(p−1)!≡−1(modp)(p-1)! \equiv -1 \pmod{p}(p−1)!≡−1(modp)
p!≡1(modp)p! \equiv 1 \pmod{p}p!≡1(modp)
(p−2)!≡1(modp)(p-2)! \equiv 1 \pmod{p}(p−2)!≡1(modp)