Which values of θ\thetaθ satisfy sin2(θ)>14\sin^2(\theta) > \frac{1}{4}sin2(θ)>41 for 0≤θ<π0 \leq \theta < \pi0≤θ<π?
0≤θ<π60 \leq \theta < \frac{\pi}{6}0≤θ<6π
π6<θ<5π6\frac{\pi}{6} < \theta < \frac{5\pi}{6}6π<θ<65π
0≤θ<π30 \leq \theta < \frac{\pi}{3}0≤θ<3π or 2π3<θ<π\frac{2\pi}{3} < \theta < \pi32π<θ<π
π6<θ<π\frac{\pi}{6} < \theta < \pi6π<θ<π