XXX has constant PDF f(x)=kf(x) = kf(x)=k on [a,b][a, b][a,b]. Relation between k,a,bk, a, bk,a,b?
k=1b−ak = \frac{1}{b-a}k=b−a1
k=1(b−a)2k = \frac{1}{(b-a)^2}k=(b−a)21
k=b−ak = b-ak=b−a
k=abk = \frac{a}{b}k=ba